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If \(cos(\theta)=3/11\) and \(\theta\) is in quadrant 1. Find \(sin(\theta).\) Round answer to 4 decimal places.

Deathstroke_rule  Apr 6, 2017
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If cos (theta)  = 3/11.....then x = 3  and r  = 11

 

And sin (theta) = y / r 

 

So we need to find y........so we have

 

y = sqrt (r^2 - x^2)   = sqrt ( 11^2 - 3^2)   =  sqrt (121 - 9)  = sqrt (112) = 4sqrt (7)

 

So.....

 

sin (theta)  =   [ 4 sqrt (7)] / 11    ≈  0.9621

 

 

 

cool cool cool

CPhill  Apr 6, 2017

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