If \(cos(\theta)=3/11\) and \(\theta\) is in quadrant 1. Find \(sin(\theta).\) Round answer to 4 decimal places.
If cos (theta) = 3/11.....then x = 3 and r = 11
And sin (theta) = y / r
So we need to find y........so we have
y = sqrt (r^2 - x^2) = sqrt ( 11^2 - 3^2) = sqrt (121 - 9) = sqrt (112) = 4sqrt (7)
So.....
sin (theta) = [ 4 sqrt (7)] / 11 ≈ 0.9621
+295 
