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Whats BC .-.

 Mar 18, 2020
 #1
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Assuming that ABCD is a trapezoid.

Drop a perpendicular from A to BC; call this point X.

Triangle(BAX) is a 30o - 60o - 90o right triangle with AB the hypotenuse.

To find AX, divide AB by the sqrt(3)   --->   AX  = 6·sqrt(3)/sqrt(3)  =  6  [this is the height of the trapezoid]

BX  =  6·sqrt(3)/2  =  3·sqrt(3).

Drop a perpendicular from D to BC; call this point Y.

XY  =  AD  =  16.

Triangle(DCY) is a 30o - 60o - 90o right triangle with CD the hypotenuse.

DY  =  AX  = 6.

YC  =  DY/sqrt(3)   --->   YC  =  6/sqrt(3)  =  2·sqrt(3).

BC  =  BX + XY + YC.

 Mar 18, 2020
 #2
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You made a couple of mestakes:

 

The height of the trapezoid  is  9   not  6

 

YC is  NOT  2*sqrt(3)        YC = 9 *sqrt(3)   

 

BC = 36.78460969 units    indecision

Guest Mar 19, 2020

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