PLEASE HELP PARABOLAS The general form of a parabola is y^2−4x+4y−8=0 .
What is the standard form of this parabola?
The standard form of a parabola's equation is generally expressed:
y=ax2+bx+c
y^2−4x+4y−8=0 . But this is a sideways parabola
Solve for x
4x = Y^2 +4y -8 divide by 4
x = 1/4 y^2 + y -2