There exist constants $a,$ $h,$ and $k$ such that \[3x^2 + 12x + 4 = a(x - h)^2 + k\]for all real numbers $x.$ Enter the ordered triple $(a,h,k).$
Please try the LaTex agian :(
Yes, I agree that the LaTeX has to be improved. Please take some time to do so.
Completing the square, we get (x + 6)^2 - 32, so (a,h,k) = (1,-6,-32).
