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Let \((a_1,b_1), (a_2,b_2), \dots, (a_n,b_n)\) be all the ordered pairs \((a,b)\) of complex numbers with \(a^2+b^2\neq 0, a+\frac{10b}{a^2+b^2}=5, \text{ and } b+\frac{10a}{a^2+b^2}=4.\) Find \(a_1 + b_1 + a_2 + b_2 + \dots + a_n + b_n.\)

 Sep 17, 2022
 #1
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The answer is 33.

 Sep 20, 2022

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