A parabola with equation $y=ax^2+bx+c$ contains the points $(-3,3)$, $(1,3)$, and $(0,0)$. Find the value $100a+10b+c$.
y = x^2/2 + x/2, so 100a + 10b + c = 100*1/2 + 10*1/2 + 0 = 55.
