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Find $4^{-1}$ (mod $35$), as a residue modulo 35. (Give an answer between 0 and 34, inclusive.)

 Jun 17, 2021
 #1
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Solved this, don't need help anymore.

 Jun 17, 2021
 #2
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4X=35N+1   where N is an integer and x is between 0 and 34

 

4*9=35+1     (by inspection)

 

so  \(4^{-1}=9 \mod{35}\)

 

I don't know if this is the only answer  indecision

 Jun 18, 2021

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