Find $4^{-1}$ (mod $35$), as a residue modulo 35. (Give an answer between 0 and 34, inclusive.)

Solved this, don't need help anymore.

4X=35N+1 where N is an integer and x is between 0 and 34

4*9=35+1 (by inspection)

so \(4^{-1}=9 \mod{35}\)

I don't know if this is the only answer