Find $4^{-1}$ (mod $35$), as a residue modulo 35. (Give an answer between 0 and 34, inclusive.)
Solved this, don't need help anymore.
4X=35N+1 where N is an integer and x is between 0 and 34
4*9=35+1 (by inspection)
so \(4^{-1}=9 \mod{35}\)
I don't know if this is the only answer
