+1 i really really dont know how to do this question and i need it done for my final
+9466 We can graph y = f(x) by picking x values and plotting points.
If x = -6, y = |x + 4| - 1 = |-6 + 4| - 1 = |-2| - 1 = 2 - 1 = 1 so (-6, 1) is on the graph. | |
| If x = -5, y = |x + 4| - 1 = |-5 + 4| - 1 = |-1| - 1 = 1 - 1 = 0 so (-5, 0) is on the graph. |
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| If x = -4, y = |x + 4| - 1 = |-4 + 4| - 1 = |0| - 1 = 0 - 1 = -1 so (-4, -1) is on the graph. | |
| If x = -3, y = |x + 4| - 1 = |-3 + 4| - 1 = |1| - 1 = 1 - 1 = 0 so (-3, 0) is on the graph. |
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| If x = -2, y = -x2 + 3 = -(-2)2 + 3 = -4 + 3 = -1 so (-2, -1) is on the graph. | |
| If x = -1, y = -x2 + 3 = -(-1)2 + 3 = -1 + 3 = 2 so (-1, 2) is on the graph. |
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| If x = 0, y = -x2 + 3 = -( 0 )2 + 3 = 0 + 3 = 3 so (0, 3) is on the graph. | |
| As we plot the points, we can see what is happening... |
|
| First we just graph f(x) = |x + 4| - 1 but we only plot the points that have an x value less than -2 |
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| Second we just graph f(x) = -x2 + 3 but we only plot the points with an x value in the interval [-2, 3) |
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| And third we would graph f(x) = x but only plot the points with an x value greater than or equal to 3 |
|
So far, these are the points we have: |
|
Notice that the point (-2, 1) is NOT on the graph and the point (-2, -1) IS on the graph.
Do you understand this so far? Do you see how to finish it? If you're still confused please say so!
+9466 We can graph y = f(x) by picking x values and plotting points.
If x = -6, y = |x + 4| - 1 = |-6 + 4| - 1 = |-2| - 1 = 2 - 1 = 1 so (-6, 1) is on the graph. | |
| If x = -5, y = |x + 4| - 1 = |-5 + 4| - 1 = |-1| - 1 = 1 - 1 = 0 so (-5, 0) is on the graph. |
|
| If x = -4, y = |x + 4| - 1 = |-4 + 4| - 1 = |0| - 1 = 0 - 1 = -1 so (-4, -1) is on the graph. | |
| If x = -3, y = |x + 4| - 1 = |-3 + 4| - 1 = |1| - 1 = 1 - 1 = 0 so (-3, 0) is on the graph. |
|
| If x = -2, y = -x2 + 3 = -(-2)2 + 3 = -4 + 3 = -1 so (-2, -1) is on the graph. | |
| If x = -1, y = -x2 + 3 = -(-1)2 + 3 = -1 + 3 = 2 so (-1, 2) is on the graph. |
|
| If x = 0, y = -x2 + 3 = -( 0 )2 + 3 = 0 + 3 = 3 so (0, 3) is on the graph. | |
| As we plot the points, we can see what is happening... |
|
| First we just graph f(x) = |x + 4| - 1 but we only plot the points that have an x value less than -2 |
|
| Second we just graph f(x) = -x2 + 3 but we only plot the points with an x value in the interval [-2, 3) |
|
| And third we would graph f(x) = x but only plot the points with an x value greater than or equal to 3 |
|
So far, these are the points we have: |
|
Notice that the point (-2, 1) is NOT on the graph and the point (-2, -1) IS on the graph.
Do you understand this so far? Do you see how to finish it? If you're still confused please say so!
