x = 78.46304097º
x/2 = 39.23152048º
sin x/2 = 0.632455532 cos x/2 = 0.774596669 tan x/2 = 0.81649658
+129852 To avoid confusion....I'm subbing theta for x
0° < theta < 90° means that x is in the first quadrant......so theta/2 will also be in the first quadrant
tan theta = 2sqrt (6) means that y =2sqrt (6) = sqrt (24) and x = 1
r = sqrt ( x^2 + y^2) = sqrt ( 1^2 + (sqrt (24))^2 ) = sqrt ( 1 + 24) = sqrt (25) = 5
cos theta = x/ r= 1/5
sin (theta/2) = sqrt [ ( 1 - cos (theta) ) /2 ] = sqrt [ (1 - 1/5) /2 ] = sqrt [ (4/5) /2 ] = sqrt [ 4/10] = (2/10)sqrt (10) = sqrt(10)/5
cos (theta/2) = sqrt [ (1 + cos (theta)) / 2 ] = sqrt [ (1 + 1/5) / 2 ] = sqrt [ (6/5)/2 ] = sqrt ( 6 ) /sqrt (10) =
sqrt (6)sqrt (10) / 10 = sqrt (60) / 10 = 2sqrt (15) / 10 = sqrt (15)/5
tan (theta/2) = 1 -cos (theta) / sin (theta) = (1 - sqrt (10)/5) / (sqrt (15)/5) =
(5 -sqrt (10)) / sqrt (15) = [ 5sqrt (15) -sqrt (10)sqrt (15) ] /15 = [ 5sqrt (15) - sqrt (150 ] / 15
please help need this ASAP
