lotta dropped a stone into a well when the air temperature was 20 degrees celcius and heard it hit water 6.58 seconds later. How far below her was the water??
+384 How does the air temperature have anything to do with the distance of water below the person? Please explain. In addition, please message to Melody or other moderators instead because I will be going away.
Thanks
GLiu
+129847 Let d be the distance to the water
The time to fall d distance is given by :
-d [meters] = (-4.9m/s^2)t^2
Rearranging this and solving for t we have
sqrt(d/4.9) = t
And, the speed of sound at 20C ≈ 343m/s
So......the time for the sound to travel from the water to the observer =
[d meters] / 343m/s =
d/343
So the total time is given by :
Time to fall + Time for sound return = 6.58 sec
sqrt(d/4.9) + d/343 = 6.58
Solving this for d, we have
d ≈ 179.712m
