Simplify and factor the expression n(n+3)-4. Show that the original expression and the factored form have the same value for n=0,1,2,3,and 4.
n(n + 3) - 4 = n^2 + 3n - 4 = (n + 4)(n - 1)
.
n(n+3)-4
2n+3n-4
If n is 0
2*0+3*0 -4
0+0-4
=4
if n is 1
2*1+3*1+-4
5-4=1
If n is 2
4+6-4
6
If n is 3
6+9-4
11
If n is 4
8+12-4
16
