please help solve this ? -3x+y-8=0 2x^2+3x-y=0

-3x + y - 8 = 0   ...(1)

2x² + 3x - y = 0 ...(2)

 

Add 3x - y to both sides of (1) to get 3x - y = -8

Put this into (2)

2x² - 8 = 0

Add 8 to both sides

2x² = 8

Divide both sides by 2

x² = 4

so x = ±2

 

Put this back into (1)

-3*(±2) + y - 8 = 0

Add 3*(±2) + 8 to both sides to get

y = ±6 + 8

or y = 14 and y = 2

 

So the two sets of solutions are x = 2, y = 14 and x = -2, y = 2

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