Define \(f(x)=\frac{1+x}{1-x}\) and \(g(x)=\frac{-2}{x+1}\). Find the value of
\(g(f(g(f(\dotsb g(f(12)) \dotsb ))))\)
where the function f is applied 8 times, and the function g is applied 8 times, alternating between the two.
Just do it
f(12)= -13/11
g(-13/11)=-2/(-2/11) = 1/11
f(1/11)=
etc
