+0

0
34
3

Define $$f(x)=\frac{1+x}{1-x}$$ and $$g(x)=\frac{-2}{x+1}$$. Find the value of

$$g(f(g(f(\dotsb g(f(12)) \dotsb ))))$$

where the function f is applied 8 times, and the function g is applied 8 times, alternating between the two.

Oct 16, 2020

#3
+111131
+1

Just do it

f(12)= -13/11

g(-13/11)=-2/(-2/11) = 1/11

f(1/11)=

etc

Oct 19, 2020