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Define \(f(x)=\frac{1+x}{1-x}\) and \(g(x)=\frac{-2}{x+1}\). Find the value of

\(g(f(g(f(\dotsb g(f(12)) \dotsb ))))\)

where the function f is applied 8 times, and the function g is applied 8 times, alternating between the two.

 Oct 16, 2020
 #3
avatar+111131 
+1

Just do it

f(12)= -13/11

g(-13/11)=-2/(-2/11) = 1/11

f(1/11)=

etc

 
 Oct 19, 2020

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