Xayden and Peter share some candies. If Xayden gives 2/5 of his share to Peter, Peter will have 156 more candies than him. If Xayden gives 3/4 of his share to Peter, Peter will have 240 more candies than him. How many candies must Peter give to Xayden so that they will have the same number of candies?
+14903 How many candies must Peter give to Xayden so that they will have the same number of candies?
Hello Guest!
\(x-\frac{2}{5}x+156=p\\ x-\frac{3}{4}x+240=p\\ x-\frac{2}{5}x+156=x-\frac{3}{4}x+240\\ \frac{3}{4}x-\frac{2}{5}x=240-156\\ \frac{7}{20}x=84\)
\(x=240\)
\(p=x-\frac{3}{4}x+240\\ p=240-\frac{3\cdot 240}{4}+240\)
\(p=300\)
\(\frac{300-240}{2}=\color{blue}30\)
30 candies must Peter give to Xayden so that they will have the same number of candies.
!
