+0  
 
+1
69
4
avatar+1850 

Please help, ty!

RainbowPanda  Aug 10, 2018
 #1
avatar+89876 
+3

a. Similar to the last one, we have

 

Avg rate of change   = [Ending height - Beginning height ] / [ Ending time - Beginning time ]

 

First 2.5 seconds

[25 - 0 ] / [ 2.5 - 0]  = 25 / 2.5   = 10 ft/sec

 

2.5 to 5

[ 0 - 25 ] / [ 5 - 2.5 ] =  -25 / 2.5  =  -10 ft/sec

 

0 to 1

[ 15 - 0 ] / [ 1 - 0 ]  =  15 ft/sec

 

1 to 2

[ 24 - 15 ] / [ 2 - 1 ] =  9/1  = 9 ft/sec

 

b. Definitely not.....the graph is a parabola.....the rates of change on a parabola are not constant

 

c. Avg rate of change  over entire 5 seconds

[  0  - 0 ]  [ 5 - 0 ] = 0/ 5   =  0 ft/sec

 

 

cool cool cool

CPhill  Aug 10, 2018
edited by CPhill  Aug 10, 2018
 #2
avatar+1850 
+1

Thank you! I honestly only wanted the formula, but thanks haha

I wanted to make sure I was doing it correctly ^-^

RainbowPanda  Aug 10, 2018
 #3
avatar+89876 
+2

OK...glad to  help where I can....smiley

 

cool cool cool

CPhill  Aug 10, 2018
 #4
avatar+1850 
+1

I really appreciate all of your help!

RainbowPanda  Aug 10, 2018

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