+0  
 
-1
95
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avatar+1407 

Let \(f(x)=2x^2-3x+4\)  and  \(g(x)=x+1\). Find the correct expression for evaluating \(g(f(5))\).

 

a) \((2(5+1)^2-3(5+1) +4) +1\)

 

b) \((2(5)^2-3(5)+4)+1\)

 

c) \((2(5+1)^2-3(5+1)+4)\)

 

d) \((2(5-1)^2-3(5-1)+4)+1\)

 Jan 17, 2021
 #1
avatar+112523 
+3

just replace the x in the g function with   2x^2-3x+4

 

and then sub 5 for x.

 

You tell us what you get.   

 Jan 17, 2021
 #2
avatar+1407 
+2

That gave me the same answer I already came up with. 

 

\(g(f(5))=2(5)^2-3(5)+4+1\)

 

I was shown how to get here but I don't know how to write the expression the way they want it.

 

Is the answer b) ? What I got looks similar to it.

SmartMathMan  Jan 18, 2021
 #3
avatar+112523 
0

what you have written is exactly the same as B.  No need to rearrange anything.

B just has one added set of brackets but they do not change the value at all.

 Jan 18, 2021
edited by Melody  Jan 18, 2021
 #4
avatar+112523 
+1
Melody  Jan 18, 2021
 #5
avatar+1407 
+1

Thank you! I'll definitely check the link out. I could use some extra practice in this area.

SmartMathMan  Jan 19, 2021

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