+0  
 
+3
75
4
avatar+266 

Please I need help with this math problem.

 

 Mar 25, 2020
 #1
avatar+111330 
+2

The red area is the difference in the area of the sector less  the area of the isosceles triangle  with the radius as its equal sides

 

Area of sector  =   pi * r^2 * (68.9  / 360)  =   pi *(9.28)^2* (68.9  / 360)     (1)

 

Area  of triangle  = (1/2) (r^2 )  sin (68.9°)  =  (1/2) (9.28)^2 sin (68.9°)   (2)

 

So.....the red area = (1)  - (2)  =

 

[ pi *(9.28)^2* (68.9  / 360) ] - [  (1/2) (9.28)^2 sin (68.9°)  ]  =

 

        51.78     -   40.17     ≈

 

            11.6  cm^2

 

 

cool cool cool

 Mar 25, 2020
 #2
avatar+266 
+2

Thank you!

Mathisgood  Mar 25, 2020
 #3
avatar+111330 
0

OK, man....glad to help where I can....

 

 

cool cool cool

CPhill  Mar 25, 2020
 #4
avatar+1970 
+2

That's the spirit! LOL!

CalTheGreat  Mar 25, 2020

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