If $\lceil x\rceil+\lfloor x\rfloor+x=4.8$, solve for $x$.
x = 2.8
let
\(x=Z+\delta\qquad \text{where Z is an integer and }0\le\delta<1\)
\(\lceil x \rceil+\lfloor x \rfloor + x = Z+1+Z+Z+\delta\\ 3Z+\delta+1=4.8\)
and you can finish it. Remember that Z is an integer and delta is between 0 and 1
