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A basketball player shoots a free throw from the foul line. The equation of the path it will travel is h = -4.9t2 + 10t + 1.2 which gives the approximate height, h, of the basketball in meters after t seconds.

 

When does the ball reach its maximum height?

 Jan 8, 2021
 #1
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h = -4.9t^2 + 10t + 1.2

==> dh/dt = -4.9t + 10

Setting dh/dt to 0 and solving for t gives t = 10/4.9 = 2.04 seconds

 Jan 8, 2021
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Thank You!

SmartMathMan  Jan 8, 2021

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