f(x)=3x+1
g(x)=4x+2/3
solve for g(f(0))
Oh my fav!! * Scarcasm *
Wouldn't the "x,y" be "0"s??
f(0) = 3(0) + 1 = 1
So
g(f(0)) = g(1) = [4(1) + 2] / 3 = [6] / 3 = 2
So, I WAS right!
* Bows *
Yw!