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Stuck on this hard geometry problem.

 

ABCD is a square.  Angle AFD = 70, angle FAE = 45.  Find angle AEF.

 

https://ds055uzetaobb.cloudfront.net/brioche/uploads/vzObmWzaBp-95715541_253420799183054_2366965139774636032_n.jpg?width=400

 May 9, 2020
 #1
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Let the side of the square be 4 inits.

 

DF = tan(20º) * 4  = 1.455880937

 

FC = 4 - DF = 2.544119063

 

BE = tan(25º) * 4 = 1.865230633

 

EC = 4 - BE = 2.134769367

 

tan(∠FEC) = FC / EC          ∠FEC = 50º

 

∠X = 180º - (65º + 50º) =  65º    indecision

 

 May 9, 2020
edited by Dragan  May 9, 2020
edited by Dragan  May 9, 2020
edited by Dragan  May 9, 2020
edited by Dragan  May 9, 2020

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