simplify assume all variebls represent non zero-numbers Algebra question (3x/y)^-5=
(3x/y)^-5=
Look at this old thread it will help you understand.
http://web2.0calc.com/questions/indices-especially-negative-indices
$$\begin{array}{rll}
&=&\left(\dfrac{3x}{y}\right)^{-5}\\\\
&=&\left(\dfrac{y}{3x}\right)^{+5}\\\\
&=&\dfrac{y^5}{(3x)^5}\\\\
&=&\dfrac{y^5}{3^5x^5}\\\\
&=&\dfrac{y^5}{243x^5}\\\\
\end{array}$$
(3x/y)^-5=
Look at this old thread it will help you understand.
http://web2.0calc.com/questions/indices-especially-negative-indices
$$\begin{array}{rll}
&=&\left(\dfrac{3x}{y}\right)^{-5}\\\\
&=&\left(\dfrac{y}{3x}\right)^{+5}\\\\
&=&\dfrac{y^5}{(3x)^5}\\\\
&=&\dfrac{y^5}{3^5x^5}\\\\
&=&\dfrac{y^5}{243x^5}\\\\
\end{array}$$