Let $a$ and $b$ be the solutions of the equation $2x^2-10x+5=0$. What is the value of $(2a-3)(4b-6)$?
By the quadratic formula, the solutions are (5 +/- sqrt(17))/2.
Plugging these in, we get
(2a - 3)(4b - 6) = (2*(5 + sqrt(17))/2 - 3)*(4*(5 - sqrt(17)/2 - 6) = -26.
