There were 5/8 as many shells as fish in an aquarium. After 50 shells and 8 fish were removed, the ratio of the number of shells to the number of fish became 1:4. Find the number of shells in the aquarium in the end.

DSUDLER4251 Oct 22, 2023

#1**+1 **

f = fish #

5/8 f = shell number

(5/8f -50) / (f-8) = 1/4 <==== solve for f ....cross multiply to get:

4 ( 5/8f-50) = f-8

20/8f - 200 = f-8

12/8 f = 192

f = 128

then ORIGINAL shells were 5/8 (128) = 80

FINAL shells = 80 - 50 =** 30 shells in the end **

ElectricPavlov Oct 23, 2023

#3**0 **

S: 1p = 5u - 50

F: 4p = 8u - 8

1p = 2u - 2

5u - 50 = 2u - 2

3u = 48

1u = 16

Shells in the end = 2(16) - 2.

Number of shelsss in end = 30

smellyboogersLoLoLoL Oct 24, 2023