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One bag contains 7 red chips and 4 yellow chips. Another bag contains 5 red chips and 3 yellow chips. A chip is drawn from each bag. What is the probability that both chips are yellow?  how do i do it step by step?

 Apr 14, 2016
edited by Guest  Apr 14, 2016
 #1
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We  have 11 chips in the first bag and 4 are yellow......so the probability of drawing a yellow chip =   4/11

 

And we have 8 chips in the next bag and 3 are yelllow......so the probability  of drawing a yellow chip = 3/8

 

And the probability of drawing a yellow chip from the first bag and then a yellow chip from the second  bag  is given by multiplying the separate probabilities......so we have....

 

[4/ 11] * [3 / 8 ]   =    { swap denominators }

 

[4 / 8]  * [ 3/ 11]  =

 

[1 / 2 ] * [ 3 / 11]  =

 

3 / 22    = about  13.64%

 

 

 

cool cool cool

 Apr 14, 2016
 #2
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P(yellow from first bag) = 4/(7+4) = 4/11 ≈ 0.3636

P(yellow from second bag) = 3/(5+3) = 3/8 = 0.375

P(both drawn chips are yellow) = (4/11) * (3/8) = 12/88 ≈ 0.1363 recurring

 

Fractions (12/88) always give an exact solution, decimal representation may not, as in this case.

 Apr 14, 2016

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