Convert the rectangular coordinates (4√3,−4) to polar form. Let r>0 and 0 ≤ θ < 2π .Enter coordinates as simplifed fractions or radicals in simplest form.
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r = sqrt [ (4√3)^2 + (-4)^2 ] = sqrt [ 48 + 16] = sqrt (64) = 8
θ = arctan (-4 / [4sqrt(3)] = arctan ( - 1/sqrt (3) ) = -pi/6 = 11pi/6
So
( r, θ) = (8, 11pi/6)
