I have been trying this problem for awhile now but i cant get it. Can someone please help?

Hannah is instructed to write down a positive, 4-digit integer. What is the probability it is an even palindrome (a number that reads the same forward and backward)? Express your answer as a common fraction.

Guest Aug 7, 2019

#1**+2 **

Even plaindromes

Starts with Ends with

2 2

4 4

6 6

8 8

We have 10 choices for the middle two numbers in each case = 40 possibiliities

We have 90 4 digit palindromes (the other 50 come from starting and ending the number with 1,3,5,7, or 9....and for each of these we have 10 possibiliites)

So....the probability of an even palindrome = 40 / 90 = 4 / 9

CPhill Aug 7, 2019

#4**+2 **

CPhill has found the probability that it is an even palidrome given that it is a palindrome.

I do think think this is quite what the question is asking.

I think it wants the probability that it is a 4 digit even palidrone given that it is a 4 digit number.

The number of 4 digit numbers is 9*10*10*10 = 9000

The answer I believe is

4/900

Melody Aug 7, 2019