+0  
 
0
126
1
avatar

At what time, t, does the object hit the ground?

 

s(t)=t^2−4t−12 

 

Solution = _____ Seconds

 

For some reason I don't understand how to do it. I've done things just like these Quadratic Functions, but because its t^2-4t-12=s(t) instead of something like t^2-4t-12=0. The two variables is throwing me off horendously. 

 

PLEASE SOMEBODY HELP ME

Guest Feb 16, 2017
 #1
avatar
0

When s = 0   the ball is on the ground

0 =t^2-4t-12

0 = (t-6)(t+2)      So t = 6     or -2 (throw this answer out...time is not neg)

t = 6

Guest Feb 16, 2017

11 Online Users

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.