I got theta = 5pi/6
Is that correct?
y = [ -sqrt (3) / 3 [ x
y / x = -sqrt (3) /3
tan θ = -sqrt (3) / 3 = - 1 /sqrt (3)
arctan (-1/sqrt 3) = -30°
Add 180 to this
θ = 150° = 5pi/ 6 good job !!!!
Thank you so much!
No prob !!!!!
