Loading [MathJax]/jax/output/SVG/jax.js
 
+0  
 
+1
804
2
avatar+159 

Given that a+b=5 and a2+b2=15, find a3+b3.

 May 19, 2019
 #1
avatar+6251 
+1

a3+b3=(a+b)(a2ab+b2)=(a+b)2=a2+b2+2ab=15+2ab=252ab=10ab=5a3+b3=5(155)=50

.
 May 19, 2019
edited by Rom  May 19, 2019
 #2
avatar+159 
0

That was much simpler than what I was thinking

 May 25, 2019

2 Online Users