Square A has a perimeter of $24$ cm. Square B has an area equal to one-fourth the area of square A. What is the perimeter of square B?
The side length of square A is \(24 \div 4 = 6\), meaning its area is \(6^2 = 36\).
Square B's area is \(36 \div 4 = 9\), meaning its side length is 3, so the perimeter is \(3 \times 4 = \color{brown}\boxed{12}\)