Find the area of the triangle bounded by the y-axis and the lines y - 3x = -2 and 3y + x = 12.
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\(y=3x-2\\ y=-\frac{1}{3}x+4\)
\(3x-2=\frac{12-x}{3}\\ 9x-6=12-x\\ 10x=18\)
\(x=1.8\)
\(A=\frac{1}{2}\cdot (4-(-2))\cdot 1.8\)
\(A=5.4\)
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