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Suppose a function $f(x)$ has domain $(-\infty,\infty)$ and range $[-11,3]$. If we define a new function $g(x)$ by $$g(x) = f(6x)+1,$$ then what is the range of $g(x)$? Express your answer in interval notation.

Guest Jul 9, 2018
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Range of f(6x) is [-11,3]. So range of g(x)=f(6x)+1 is [-10,4]

MaxWong  Jul 15, 2018