There are two triangles satisfying \(\angle BCA = 60^{\circ}, AB = 9\) and \(AC = 10\) shown below:The possible values of \(BC\) are \(a_1\) and \(a_2\) as shown in the picture with \(a_1\)<\(a_2\). Then what are \(a_1\), \(a_2\) in that order?
By the Law of Cosines, a_1 = 6 - 2*sqrt(2) and a_2 = 6 + 2*sqrt(2).
+4 
