+0

0
126
3

What is the least integer greater than $\sqrt{300}$?

Jul 6, 2021

#1
+238
+2

Think of the perfect squares around 300. 17^2 = 289, 18^2 = 324. $$\sqrt{324} = 18$$ as we know, so 18 is the least integer greater than $\sqrt{300}$

Jul 6, 2021

#1
+238
+2

Think of the perfect squares around 300. 17^2 = 289, 18^2 = 324. $$\sqrt{324} = 18$$ as we know, so 18 is the least integer greater than $\sqrt{300}$

Awesomeguy Jul 6, 2021
#2
+1

That was quick, thank you so much!

Guest Jul 6, 2021
#3
+857
0

$\lceil{\sqrt{300}}\rceil = \lceil{\sqrt{3 \cdot 100}}\rceil = \lceil{10 \sqrt{3}}\rceil \approx \lceil{10 \cdot 1.73}\rceil = \lceil{17.3}\rceil = \boxed{18}$