+0  
 
0
375
3
avatar

What is the least integer greater than $\sqrt{300}$?

 Jul 6, 2021

Best Answer 

 #1
avatar+240 
+2

Think of the perfect squares around 300. 17^2 = 289, 18^2 = 324. \(\sqrt{324} = 18\) as we know, so 18 is the least integer greater than $\sqrt{300}$

 Jul 6, 2021
 #1
avatar+240 
+2
Best Answer

Think of the perfect squares around 300. 17^2 = 289, 18^2 = 324. \(\sqrt{324} = 18\) as we know, so 18 is the least integer greater than $\sqrt{300}$

Awesomeguy Jul 6, 2021
 #2
avatar
+1

That was quick, thank you so much!

Guest Jul 6, 2021
 #3
avatar+876 
0

$\lceil{\sqrt{300}}\rceil = \lceil{\sqrt{3 \cdot 100}}\rceil = \lceil{10 \sqrt{3}}\rceil \approx \lceil{10 \cdot 1.73}\rceil = \lceil{17.3}\rceil = \boxed{18}$


1 Online Users

avatar