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What is the least integer greater than $\sqrt{300}$?

 Jul 6, 2021

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 #1
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Think of the perfect squares around 300. 17^2 = 289, 18^2 = 324. \(\sqrt{324} = 18\) as we know, so 18 is the least integer greater than $\sqrt{300}$

 Jul 6, 2021
 #1
avatar+234 
+2
Best Answer

Think of the perfect squares around 300. 17^2 = 289, 18^2 = 324. \(\sqrt{324} = 18\) as we know, so 18 is the least integer greater than $\sqrt{300}$

Awesomeguy Jul 6, 2021
 #2
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+1

That was quick, thank you so much!

Guest Jul 6, 2021
 #3
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$\lceil{\sqrt{300}}\rceil = \lceil{\sqrt{3 \cdot 100}}\rceil = \lceil{10 \sqrt{3}}\rceil \approx \lceil{10 \cdot 1.73}\rceil = \lceil{17.3}\rceil = \boxed{18}$


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