Jeri finds a pile of money with at least 200. If she puts 50 of the pile in her left pocket, gives away 2/3 of the rest of the pile, and then puts the rest in her right pocket, she'll have more money than if she instead gave away 200 of the original pile and kept the rest. What are the possible values of the number of dollars in the original pile of money? (Give your answer as an interval.)
+128454 See the answer here : https://web2.0calc.com/questions/help-asap_81716
+128454 OK.....here's what I get.......
Let x be the additional amount over the original $200
The greater side of the inequality is
Original pile = (200 + x)
After she gives away $50 she has (150 + x)
And she gives (2/3) of this away = (2/3) (150 + x)
So....she must have (1/3) of this left = (1/3)(150 + x) = amt in her right pocket
The lesser side of the inequality is
(x + 200) - 200 = x
So we have that
[150 + x ] / 3 > x
150 + x > 3x
150 > 2x
75 > x
x < 75
So...I get that the original amount could be on this interval (200 , 275)
