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Jeri finds a pile of money with at least 200. If she puts 50 of the pile in her left pocket, gives away 2/3 of the rest of the pile, and then puts the rest in her right pocket, she'll have more money than if she instead gave away 200 of the original pile and kept the rest. What are the possible values of the number of dollars in the original pile of money? (Give your answer as an interval.)

 Mar 5, 2020
 #1
avatar+111436 
+1

See the answer  here  :  https://web2.0calc.com/questions/help-asap_81716

 

 

cool cool cool

 Mar 5, 2020
 #2
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0

But when i put it in, it said it was wrong...

 Mar 5, 2020
 #3
avatar+111436 
+1

OK.....here's what  I  get.......

 

Let x be  the  additional amount over the  original $200

 

The greater side of the  inequality  is

 

Original  pile  =  (200 + x)

 

After  she gives away  $50  she has   (150 + x)

 

And  she gives (2/3)  of  this away  =  (2/3) (150 + x)

 

So....she  must  have  (1/3)  of this left =  (1/3)(150 + x) = amt in her right pocket

 

The lesser  side of the inequality  is

 

(x + 200)  -  200   =   x

 

So  we  have  that

 

[150 + x ] / 3  >    x

 

150 + x  >  3x

 

150  >  2x

 

75 > x

 

x < 75 

 

So...I get  that  the original  amount  could be on this interval   (200 , 275)

 

 

cool cool cool

 Mar 5, 2020
 #4
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0

what bracket do i use?

 Mar 7, 2020

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