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The roots of x^2 + 5x + 3 = 0 are p and q, and the roots of x^2 + bx + c = 0 are p^2 and q^2. Find b + c.

 Jun 29, 2020
 #1
avatar+26637 
+2

Using quadratic formula I find rootp and q to be

-5/2 +- (sqrt13)/2       or      x=−0.697224    x=−4.30278

 

square them to get  p^2   and q^2    = .486121    and     18.51388

 

(x-.486121) (x-18.51388)   = x^2 - 19x + 9 = 0      

Now you can add b+ c 

 

   or you could do it the hard way and multiply out all of those radicals !

 Jun 29, 2020
 #2
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0

I got 28 but it was wrong...

Guest Jun 29, 2020
 #3
avatar+26637 
+1

Silly....   - 19 + 9   does not equal 28 now does it??????

ElectricPavlov  Jun 29, 2020

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