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The equation \($y = -16t^2 + 26t + 105$\)describes the height (in feet) of a ball tossed up in the air at 26 feet per second from a height of 105 feet above the ground. In how many seconds will the ball hit the ground? Express your answer as a decimal rounded to the nearest tenth.

 Jun 18, 2021
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y is the height of the ball....    when y = 0   the ball is on the ground

 

0 = -16t^2 + 26t+ 105         Now use the Quadratic Formula   to find the 't' values  

                                   \(t = {-26 \pm \sqrt{26^2-4(-16)(105)} \over 2(-16)}\)          a = -16     b = 26    c = 105     (throw out the negative 't' value)

 Jun 18, 2021

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