The equation \($y = -16t^2 + 26t + 105$\)describes the height (in feet) of a ball tossed up in the air at 26 feet per second from a height of 105 feet above the ground. In how many seconds will the ball hit the ground? Express your answer as a decimal rounded to the nearest tenth.
+36916 y is the height of the ball.... when y = 0 the ball is on the ground
0 = -16t^2 + 26t+ 105 Now use the Quadratic Formula to find the 't' values
\(t = {-26 \pm \sqrt{26^2-4(-16)(105)} \over 2(-16)}\) a = -16 b = 26 c = 105 (throw out the negative 't' value)
