+113 The center of the circle with equation x^2+y^2=4x+12y-39 is the point (h,k). What is h+k?
+37153 x^2+y^2=4x+12y-39
Get it in standard form (x-h)^2 + (y-k)^2 = r^2
x^2-4x + y^2-12y = -39 'complete the square ' for x and y
x^2 -4x +4 + y^2-12y+36 = -39 + 4 + 36
(x-2)^2 + (y-6)^2 = 1 Now you can see what h and k are and add them together for your answer.....
