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Can anyone help on this?  I'm very stuck.

 

A, B, C, D are points on a circle.

 

PA is tangent to the circle.

 

Angle PAD = 39 degrees, and angle BCD = 103 degrees.

 

BD is not a diameter.

 

Find angle ADB.

 

 May 12, 2020
 #1
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Since angle(BCD) = 103o, arc(BAD) = 2 x 103o = 206o.

Since angle(PAD) is formed by a tangent and a chord, arc(AD) = 2 x 39o = 78o.

Therefore, arc(BA) = 206o - 78o = 128o.

Angle(ADB) =  ½ x arc( BA) = ½ x 128o = 64o.

 May 12, 2020

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