Can anyone help on this? I'm very stuck.
A, B, C, D are points on a circle.
PA is tangent to the circle.
Angle PAD = 39 degrees, and angle BCD = 103 degrees.
BD is not a diameter.
Find angle ADB.
Since angle(BCD) = 103o, arc(BAD) = 2 x 103o = 206o.
Since angle(PAD) is formed by a tangent and a chord, arc(AD) = 2 x 39o = 78o.
Therefore, arc(BA) = 206o - 78o = 128o.
Angle(ADB) = ½ x arc( BA) = ½ x 128o = 64o.