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Suppose in a math class of 22 students, 14 are boys and 8 are girls. On the final exam, 4 boys and 6 girls made an A grade.

1) If a student is chosen at random from the class, what is the probability of choosing a girl or an A student?

A)10/11

B)2/11

C)3/11

D)6/11

 

2) If a student is chosen at random from the class, what is the probability of choosing a boy or an A student?

A)10/11

B)2/11

C)3/11

D)6/11

 Mar 28, 2019
 #1
avatar+19326 
+1

for a girl you have a   8 out of 22 students chance....for an A you have an additional 4 (boys) out of 22 chance

8/22+4/22 = 12/22 = 6/11

 

for a boy there is a 14 out of 22 chance of being a boy   and an andditional 6 (girls) out of 22 for an A

14/22 + 6/22 = 20/22= 10/11

 

 

(Not ABSOLUTELY positive of this....but ....mostly ! cheeky)

 Mar 29, 2019
 #2
avatar+6043 
+1

10/11 is correct

 

14/22 + 10/22 - 4/22 = 20/22 = 10/11

Rom  Mar 29, 2019

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