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The vertex of the parabola described by the equation 3y=2x^2-16x+18 is (m, n). What is m+n?

 Jun 26, 2020
 #1
avatar+28021 
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3y=2x^2-16x+18

y = 2/3 x^2 - 16/3 x + 18/3      vertex is at   x = -b/2a        b = -16/3    a = 2/3

    when you calculate this value of 'x',

            find the 'y' value of the vertex by substituting this value of 'x' into the equation

 Jun 26, 2020
 #2
avatar+112 
0

Ok, Thank you so much.

QuestionsBug  Jun 26, 2020

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