The vertex of the parabola described by the equation 3y=2x^2-16x+18 is (m, n). What is m+n?
y = 2/3 x^2 - 16/3 x + 18/3 vertex is at x = -b/2a b = -16/3 a = 2/3
when you calculate this value of 'x',
find the 'y' value of the vertex by substituting this value of 'x' into the equation