please help!!!

 Feb 16, 2019


 Feb 16, 2019

If we assume that "the graph consists of three line segments," then we can generate the equation of the lines. 


Of course, I could use \(y=mx+b\), but that would require me to know the y-intercept of the first red line, and, unfortunately, the y-intercept is not clear-cut in the image.


I will use point-slope form instead; this form requires me to know the coordinates of any  two points on that line. \(y-y_1=m(x-x_1)\) is the form of point-slope form. \((x_1,y_1)\) is the coordinate of any one point of the line. In the image, I can pinpoint that \((-4,4)\text{ and }(-1,-1)\) both lie on the line I care about for this problem. Now that they are identified, I can now find the slope.




I will substitute in the point \((-1,-1)\) as my point.


Since we are trying to find \(f(-2)\) , x=-2.


\(y_1=-1;m=-\frac{5}{3};x=-2;x_1=-1\\ y-y_1=m(x-x_1)\\ y-(-1)=-\frac{5}{3}(-2-(-1))\) It is time to solve for y!
\(y+1=-\frac{5}{3}*-1\\ y+\frac{3}{3}=\frac{5}{3}\\ y=\frac{2}{3}\)  


\(f(-2)=\frac{2}{3}\). You will see that this answer is consistent with the initially given diagram.


 Feb 16, 2019

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