Find positive integers m and n such that 5m + 7n = 46.
m = 5 & n = 3 will work.
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m=−\(\frac{5}{7}\) n+\(\frac{46}{5}\)
n=−\(\frac{5}{7}\)m+\(\frac{46}{5}\)
my favorite method when i can't solve a problem is trial and error