Two points A and B are on opposite sides of a building. A surveyor selects a third point C to place a transit. Point C is 52 feet from point A and 67 feet from point B. The angle ACB is 60°. How far apart are points A and B?

Guest May 13, 2021

#1**+1 **

Use Law of Cosines

52^{2} + 67^{2} - 2 (52)(67)cos(60) = (AB)^{2 }I'll let you finish with the calculations !

ElectricPavlov May 13, 2021