The perimeter of the rectangle below is 114 units. Find the length of side PQ.

Perimeter is the sum of the two sides given * 2

(2x-1 + 3x+3) * 2 = 114

solve for 'x' then PQ = 3x+3

SP + PQ = 114/2 solve for x

We know that the perimeter is equal to 2x-1+2x-1+3x+3+3x+3=144 which can be simplfied to 4x-2+6x+6=114 and then 10x+4=114 we then subtract 4 to get 110 and divide by 10 to get x=11 so PQ=11*3+3=33+3=36 and we have that PQ=36 or \(\boxed{PQ=36}\)