If the pressure of a gas doubles, how does the absolute temperature change?
\(pV = n R T\)
\(T_1 = \dfrac{pV}{nR} \\ T_2 = \dfrac{2pV}{nR} \\ \dfrac{T_2}{T_1} = 2\\ \text{i.e. the temperature doubles when you double the pressure}\)
thx soo much
+1438 
