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Please help! Thank you!!

mathelp  Aug 24, 2018
 #1
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Square  with a "radius"  of 11m

The "radius"  is the distance from the center of the square to any vertex

The area is  4(1/2)11^2  = 2 * 121  = 242 m^2

 

 

Pentagon with a side of 9m

The pentagon will be composed of 5 congruent triangles

The height of each is given  by  (9/2)/tan (36°)

So...the total area is

5 (1/2)(9)(9/2)/tan(36°)  =  (5)(9/2)^2/tan(36°)  ≈  139.4 m^2

 

 

Pentagon  with a radius of 5m

We have 5 congruent triangles with sides of 5 and an included angle of 72° between these sides

The area  =   5 (1/2) (5)^2sin (72°) ≈  59.4m^2

 

 

Hexagon with a side of 12 yd

We have six congruent equilateral triangles...each side  = 12 yd

The area is  6(1/2)(12)^2* √3/2  ≈  216√3  yds^2 ≈ 374.1 yds^2

 

 

cool cool cool

CPhill  Aug 24, 2018
edited by CPhill  Aug 24, 2018
edited by CPhill  Aug 24, 2018

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