Jhovanna found four consecutive integers such that three times the sum of the first and the fourth was 114 less than the product of -5 and the sum of the first two. What were the integers?
+36916 x x+1 x+2 x+3 are the integers
3 ( x + x+3) = -5 ( x + x+1) - 114 solve for x
6x + 9 = -10x -5 - 114
16x = - 128
x = -8
-8 -7 -6 -5
