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Jhovanna found four consecutive integers such that three times the sum of the first and the fourth was 114 less than the product of -5 and the sum of the first two. What were the integers?

 Mar 13, 2020
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x        x+1       x+2        x+3     are the integers

 

3 ( x +  x+3)   = -5 ( x   +   x+1)   - 114       solve for x

6x + 9 = -10x -5 - 114

16x = - 128

x = -8

 

-8     -7     -6     -5     

 Mar 13, 2020

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