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Two candles of the same height are lit at the same time. The first is consumed in 4 hours and the second in 3 hours. Assuming that each candle burns at a constant rate, in how many hours after being lit is the first candle twice the height of the second?

 Jul 20, 2020
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The first candle burns at rate   1 candle / 4 hrs

    multiply rate * time   to get amount burned    1/4 t

       the amount REMAINING  is    1 candle - 1/4 t    = 1- 1/4t

 Similarly for the SECOND candle, the amount remaining is   1 - 1/3 t

We want the time for the length of first to be 2 times length of second:

1-1/4t   =  2   *   (1 - 1/3t)     solve for   t = ........ hrs

 Jul 20, 2020

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